625-200x+12x^2=0

Solution for 625-200x+12x^2=0 equation:

625-200x+12x^2=0

a = 12; b = -200; c = +625;
Δ = b2-4ac
Δ = -2002-4·12·625
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-100}{2*12}=\frac{100}{24}
=4+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+100}{2*12}=\frac{300}{24}
=12+1/2
$